Question

Consider the equation r=15/3-2cos(theta)...

The graph of this polar equation is an elipse and one of the elipse's foci is at the pole. To find the rectangular equation for this elipse, begin by rewriting the equation as 3r-2rcos(theta)=15. Then use the substitution r=squareroot of (x^2+y^2) and rcos(theta)=x to find the rectangular equation. After you find the rectangular equation, write it in standard form:

Answer 1

3√(x^2+y^2)-2x=15 ... this is the polar equation, need rectangular equation