Question

For the equation find the equation of the graph that is parallel and perpendicular that passes through the specified point. Then graph the equations

3x - y = 9

Answer 1

ok so basically lets start off with what the parallel slope is...so whats the parallel slope of 3x-y=9 @MSFFL

Answer 2

-y = -3x + 9 which ends up being y = 3x +9 so 3 is the slope

Answer 3

what is the specified point

Answer 4

the specified points are (1,1)

Answer 5

now how does -y=-3x+9 become y=3x+9? impossible

Answer 6

two signs must change for the problem to remain the same

Answer 7

I learned it early on when I was changing sign in fractions

Answer 8

the parallel line has the same gradient

the given line in y = 3x - 9 m = 3

so the parallel line is

y - 1=3(x - 1)

y =3x -2

the perpendicular line has a gradient of -1/m in this question its -1/3

so

y - 1 = -1/3(x -1)

y = 1/3x + 4/3

Answer 9

I got that far now graphing is what I am having problems with how to you graph
1. y = 3x +9

2. y = 3x - 2

and

3. y = -1/3 + 4/3

Answer 10

ok so remember y=mx+b form? b=y intercept

Answer 11

yep

Answer 12

just use a table of values for the line y = 3x -2