Finding the area!
find the surface area
is that a triangular base? or a square base?
it is a triangle
triangular. That's why I don't understand
(bh/2)4 right? since it's composed of 4 equilateral faces..
They're equilateral? @lgbasallote
well...it wasnt stated nor shown that it wasnt right? normally people assume it's equilateral if it's like that...
So how do I fin the base? @lgbasallote
hmmm..uncle rhaurkus said it was a triangular base so it's the same with the faces...the surface area = (bh/2)4 or 2bh
so what do you do?
b= 13 h =11 2bh = 2(13)(11)
286? I don't divide it by two? @lgbasallote
it's (bh/2)4 remember? so the 2 gets canceled and give you 2bh
The triangular faces cannot be equilateral with a base of 13 and an altitude of 11 drawn to that base. The altitude would have to be 6.5 sqrt(3) which does not equal 11.
oh my gosh, I am so bad at geometric shapes. Do I use Soh Cah Toa?
This problem, in my opinion, is defective because there are no instructions. In Euclidean Geometry, eye-balling lengths is not allowed. By instructions, I mean something like what you see on the attachment.
I agree, the information given is too little.
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