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Ill be honest i have no idea abou this one Find the product of (x + 3)(x − 3). x2 − 6x + 9 x2 + 6x + 9 x2 + 9 x2 − 9
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\[(x+3)(x-3)=x(x-3)+3(x-3)\]Can you finish it from there?
x2 + 6x + 9 this one?
Not quite.\[x(x−3)+3(x−3)=x^2-3x+3x-9=x^2-9\]
16x2 − 9y2 i am pretty sure its this one maybe......
You want to factor \(16x^2-9y^2\) correct?
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x2 − 6x + 9 ok i am really sure this is it :p lol
First notice that both terms are perfect squares. Then, by the pattern we can observe from solving \((x+3)(x-3)=x^2-9\). Thus, \[16x^2-9y^2=(4x+3y)(4x-3y)\]
And \((x+3)(x-3)=x^2-9\)
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