Mathematics
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OpenStudy (anonymous):
Select one of the factors of x2 + 11x + 24
I answered (x + 3) would this be correct?
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OpenStudy (amistre64):
when x=-3 does the expression equal 0?
jhonyy9 (jhonyy9):
(x+3)(x+8)
OpenStudy (anonymous):
As in (x + 3)(x + 8)
OpenStudy (anonymous):
Ami, that's how I could check it?
OpenStudy (amistre64):
yep
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OpenStudy (anonymous):
Sweet! Didn't realize that.
OpenStudy (amistre64):
if (x+a) is a factor; then when x=-a your expression equals zero
OpenStudy (anonymous):
Wait, so if a is already a negative, what would I do?
OpenStudy (anonymous):
(x + (-a))?
OpenStudy (amistre64):
x+(-a) ; then x=-(-a) = a
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OpenStudy (anonymous):
Alright, thanks a bunch!
OpenStudy (amistre64):
whatever x value that makes your factor go zero :)
OpenStudy (amistre64):
x+3 = 0 when x=-3
x-9 = 0 when x=9
OpenStudy (anonymous):
In my case, I would replace the variable "x" with -3?
-3^2 + 11(-3) + 24?
OpenStudy (amistre64):
yes
(-3)^2 +11(-3) + 24 ?= 0
9 -33 +24 ?= 0
-24 + 24 = 0
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OpenStudy (anonymous):
-3^2 = 9
9 - 33 + 24
-33 + 33 = 0
OpenStudy (anonymous):
Yes! :D
OpenStudy (amistre64):
any x value that makes it go zero will be a root; and hence you can construct a factor from it
OpenStudy (anonymous):
Thank you! Factoring is making a lot more sense now.
OpenStudy (amistre64):
:) good luck