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Find an equation in standard form of the line through p(-5,2) and having the slope -3
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Standard like ax+b?
Umm, sorry, was away :( The formula to find a straight-line equation is y – y1 = m(x – x1)
Where m is the slope and x1 and y1 is the point. (x,y)
So you do y - (2) = (-3)(x - (-5)) y - 2 = -3 (x+5) y - 2 = -3x + -15 y - 2 = -3x -15 y = -3x - 15 + 2 y = -3x - 13 :))
And it's important to always verify your equation every time, you just have to plug the x from the point and find out if y is the same as the y from the point. y = -3(-5) -13 y = 15 -13 y = 2 So the equation is right.
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