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find the slope of the line through the pair of points. (6,-9) and (-3,5)
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Use slope = delta y / delta x
Delta y = y2 - y1 Delta x = x2 - x1
\[slope= y2-y1 \div x2-x1 = 5--9\div -3-6\]= 14/-9=-1.56
@jesuskim m=[(-3)-(6)]/[(5)-(-9)] = -9/14 You did dx/dy :P
whoops my mistake. -14/9 is correct. I went and did dx/dy instead of dy/dx sorry! thanks for finding it
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the slope of the line is given by the equation: slope(m) = rise/run = (dy/dx) dy means change in the y values, and dx means the change in the x values. so since the points are given in (x,y) fashion, you can set the equation up as follows: m=[(5)-(-9)]/[(-3)-(6)] = -14/9 goodluck!
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