Two children are riding on a merry-go-round. Child A sits at a greater distance from the axis of rotation than child B. Which child has the larger centripetal velocity? A) A B) B C) They have the same non-zero centripetal velocity. D) There is no way to determine without knowing the applied force. I chose B, because it has a smaller distance from the axis of rotation. I'd assume that a greater distance would decrease the number. Did I think it through wrong?
there is nothing called centripetal velocity if there is then it is always zero in circular motion...
wich is centripetal velocity???|dw:1334741601487:dw|
for linear velocity and centripetal acceleration,they are more for A
Of course. I was trying to remember centripetal acceleration. But sadly one of my partners has my notes so I can't look over at those right away. Thank you so much!
you are welcome!
a=v^2/r a=(ω*r)^2/r a=ω^2*r r1>r2 =>a1>a2
P.S:omega (angular velocity) is same for both..and rest is as mos163 said..
+1472
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