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Write z = 1-i in trigonometric(polar)form, where the argument "theta" satisfies 0<= "theta" < 2 pie
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For z= x-iy \[r=\sqrt{x ^{2}+y ^{2}}\]\[r=\sqrt{1^{2}+(-1)^{2}}\]\[r=\sqrt{2}\]\[\tan \theta= (-1/1)\]\[\theta=-45\]or\[\theta=360-45\]\[\theta=315\]\[\sqrt{2}(\cos315+\sin315)\]
thanks, how do I know when to use sin, cos or tan to get to the answer?
1. I would plot the point first in the complex plane and note the quadrant. 2. Then I would draw a line segment, from the orgin to the point.. 3. From there you can always find theta by noting the right triangle formed by the x-axis, y-axis and the point.
Thanks for all your help
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