Question

Solve the following system of linear equations by the elimination method.

13x+3y=32
3x-2y=2

Answer 1

Can you multiply the first one by 2 and the second one by 3?

Answer 2

let me try, hang on

Answer 3

no that doesnt work:[

Answer 4

Alright there:
(13x+3y=32)*2
(13x+3y)*2 = 32*2
13x*2 + 3y*2 = 64
26x + 6y = 64

Now try for the second one with 3 ;D

Answer 5

the second one would be 9x-18y=6
now what do i do?

Answer 6

Nope, it would be
(3x-2y)*3=2*3
9x - 6y = 6

Answer 7

oh your right, wow im dumb today haha. thank you! I just have one more problem i need help with:

Answer 8

-2/5x-1/2y=-1/3
-8/5x-2y=-4/3

Answer 9

26x + 6y = 64
9x - 6y = 6

You have this
6y cancels out

35x = 70
x = 2

Answer 10

yeah i got the answer, thank you!

Answer 11

Okay, you have -2/5x - 1/2y = -1/3
It's equal to 2/5x + 1/2y = 1/3

Now you have
2/5x + 1/2y = 1/3
-8/5x - 2y = -4/3

+1/2 and -2y could be cancelled out, but you have to do something so in the first equation, 1/2y turns into a 2y

Answer 12

so y would equal 2 and so what would x equal?

Answer 13

You plug the y(2) into any equation and solve for x :)

Answer 14

ok yeah, i just did that and i got up to this point: 4/5x+2y=1/3, now what? im so bad with fractions

Answer 15

2/5x + 1/2y = 1/3

1/2 = 0.5
2/0.5 = 4
So you have multiply everything by 4
(2/5x + 1/2y)*4 = (1/3)*4
8/5x + 2y = 4/3

You have now
8/5x + 2y = 4/3
-8/5x - 2y= -4/3

Solve :)

Answer 16

so x is no solution?

Answer 17

Umm, lemme see

Answer 18

x would be 1

Answer 19

and y would be 2?

Answer 20

It would be 2/3

Answer 21

owait, I don't get it this one o.o

Answer 22

haha its okay, thanks anyways!

Answer 23

@apoorvk