Question

PQR has vertices P(–8, 7), Q(–4, –6), and R(6, 5). It is translated left 3 units and down 2 units. Find the coordinates of P', Q', and R'

Answer 1

can u help me

Answer 2

subtract all x values by 3
subtract all y values by 2

Answer 3

^what @alexwee123 said is absolutely right.

Answer 4

P'(–11, 5), Q'(–7, –8), R'(3, 3)
P'(–5, 9), Q'(–1, –4), R'(9, 7)
P'(–5, 5), Q'(–1, –8), R'(9, 3)
P'(–11, 9), Q'(–7, –4), R'(3, 7)

Answer 5

PQR has vertices P(–8, 7), Q(–4, –6), and R(6, 5). It is translated left 3 units and down 2 units. Find the coordinates of P', Q', and R'.

Answer 6

@omarion , alexwee123 just told you what you need to do.
Okay, I 'll show you one for example. Let's take point P.
P(-8,7)
Since its translated 3 units to the left and 2 to the bottom, we need to account for that change in their rectangular co-ordinates of the point P.
so we deduct 3 from its x-coordinate, and 2 from its y-coordinates.

so P' = (-8-3 , 7-2)

or, P' ---> (-11, 5)

Answer 7

can you do the rest? its simple enough.