Question

Can someone help me with this problem:

(x+3) (x^2-2x+1)

Can you possibly explain it to me as well

Answer 1

Use the idea that (A+B)(C+D+E) = A(C+D+E) + B(C+D+E) and simplify to get...


(x+3)(x^2-2x+1)


x(x^2-2x+1)+3(x^2-2x+1)


x^3-2x^2+x+3x^2-6x+3


x^3+x^2-5x+3



So the expression expands and simplifies to x^3+x^2-5x+3

Answer 2

lead me through the process, please

Answer 3

Let me know if that helps. If not, I can try another way.

Answer 4

can you explain it please

Answer 5

In general, (A+B)(C+D+E) = A(C+D+E) + B(C+D+E)

Answer 6

so use this to transform (x+3)(x^2-2x+1) into x(x^2-2x+1)+3(x^2-2x+1)

Answer 7

it's like a form of distribution

Answer 8

next, distribute each group


so distribute x to x^2-2x+1 to get


x(x^2-2x+1) = x^3 - 2x^2 + x


--------------------------------

then distribute 3 to x^2-2x+1 to get


3(x^2-2x+1) = 3x^2 - 6x + 3

Answer 9

so x(x^2-2x+1)+3(x^2-2x+1) then becomes


x^3 - 2x^2 + x + 3x^2 - 6x + 3


from here, all you need to do is combine like terms


so add -2x^2 and 3x^2 to get x^2

and add x and -6x to get -5x


giving you the final answer of


x^3 + x^2 - 5x + 3

Answer 10

Let me know if this makes sense or not.

Answer 11

will do, thanks