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f(x)=x^(-.5) how do I rewrite this with a positive radical?
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x^-a = 1/x^a
f(x) = 1/sqrt(x)
Can you see what it will be from what i wrote?
is it \[1/x^{.5}\]then?
.5 = 1/2 right so x^.5= x^1/2 and we know that x^a/b =\[\sqrt[a]{x^{b}}\]
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so its going to be 1/ squareroot (x)
Algebraically how do I get rid of a sqrt that is on the bottom of a fraction? I haven't taken any math for like 2 years so I cant remember some stuff haha. for example am doing the limit at a point so I will have |dw:1334783367531:dw| how do I get rid of the square root to solve for h?
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