Question

A ramp represented by segment PQ in the figure below is used to load cargo on a truck. Maya wants to find the length of the ramp. I think the answer is B.

Answer 1

Do you have your work for this? I think you are correct, I just want to make sure. :P

Answer 2

considering triangle TQS sin\[\theta\]=opposite which is 12/hypothenus 16
sin(theta)=12/16
sin(theta)=3/4
(theta)=\[\sin^{-1} 3/4\].......eqtn 1
the value for you (theta) is TQS
then you consider triangle RQP
using right-angle law
we have sin(theta)=opposite which is 18 divided hypothenus which is the total length/PQ/
remember your answer in equation 1 ,you substitute it in you theta value when you are considering triangle RQP
you make the hypothenus the subject so you have
/PQ/=18 divided by sin(theta)
and thats your answer

Answer 3

sorry not with calculate here,i would have done the sin aspect of the calculation

Answer 4

Your computer doesnt have one?

Answer 5

I just used the fact that the triangles were similar (by AA~, they share an angle Q and a 90 degree angle) and set up a similarity ratio:
12/16 = 18/PQ
12 PQ = 16*18
12 PQ = 288
PQ = 24