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Find an equation for the plane K that is parallel to N which is defined by the equation 4x-3y-6z=12 and passes through the point (2, 3, -1)
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pull off the normal and plug in the point
parallel lanes have the same normal vectors
So, I would plug (2, 3, -1) into 4x-3y-6z and find what that equals then the equation for plane k is the 4x-3y-6z=the answer I just found?
first, write up the standard equation of a plane. a(x-Px)+b(y-Py)+c(z-Pz) the abc parts are the same as the coeefs in the other eq; 4, -3, -6 next, plug in the point they give you (Px,Py,Pz)
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