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Mathematics 13 Online
OpenStudy (anonymous):

Find an equation for the plane K that is parallel to N which is defined by the equation 4x-3y-6z=12 and passes through the point (2, 3, -1)

OpenStudy (amistre64):

pull off the normal and plug in the point

OpenStudy (amistre64):

parallel lanes have the same normal vectors

OpenStudy (anonymous):

So, I would plug (2, 3, -1) into 4x-3y-6z and find what that equals then the equation for plane k is the 4x-3y-6z=the answer I just found?

OpenStudy (amistre64):

first, write up the standard equation of a plane. a(x-Px)+b(y-Py)+c(z-Pz) the abc parts are the same as the coeefs in the other eq; 4, -3, -6 next, plug in the point they give you (Px,Py,Pz)

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