Find the smaller solution for
3/5x^2−7=21

Question

Find the smaller solution for
3/5x^2−7=21

anonymous · Answer

x^2 = 3/140

anonymous · Answer

what ?

anonymous · Answer

what is wrong?

anonymous · Answer

what are you saying !?

anonymous · Answer

x to the power of 2= 3 divided by 140

anonymous · Answer

thats wrong :(

anonymous · Answer

are you sure?

anonymous · Answer

yes :/

anonymous · Answer

there are other simplifications... that is just one of them

anonymous · Answer

thanks either way -.-

asnaseer · Answer

is this your question?$$\frac{3}{5}x^2-7=21$$

anonymous · Answer

yes !

asnaseer · Answer

ok, then we get:$$\frac{3}{5}x^2=21+7=28$$$$3x^2=5*28=140$$$$x^2=\frac{140}{3}$$

anonymous · Answer

but you have to find the square root

asnaseer · Answer

so then you just take the square root to get x = plus/minus some value

asnaseer · Answer

also, what do you mean by smaller solution?
e.g. if answer is $\pm10$, then do you mean -10 as this is less than +10?

anonymous · Answer

yea whatever the answer is i just put negative and it should be right

asnaseer · Answer

ok, so you should be able to find the answer now from what I have given you above

anonymous · Answer

can you just tell me please am being timed

zepp · Answer

Okay, from there
$$x^2 = 140/3$$
You know that $$a^2 = b$$ could also be $$a =\sqrt {b}$$

Now do the same thing with it and it will give
$$x = \pm\sqrt {140/3}$$

The smallest value would be
$$x = - \sqrt {140/3}$$

the only thing you have to do is to simplify it