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Mathematics 15 Online
OpenStudy (anonymous):

by working out my problem can someone check it: sec^2-tan^2 (1/cos x1/cos)- (sin/cos x sin/cos) 1/cos^2-sin^2/cos^2 1-sin^2/cos^2 cos^2/cos^2 =1

OpenStudy (inkyvoyd):

That should be correct, but theres a much faster way.

OpenStudy (inkyvoyd):

Start from sin^2+cos^2=1

OpenStudy (inkyvoyd):

divide both sides by cos^2

OpenStudy (inkyvoyd):

rearrange to make it sec^2-tan^2

OpenStudy (inkyvoyd):

????

OpenStudy (inkyvoyd):

Profit.

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

thats right

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