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taylor series of f(x)=sin(x), a=pi/2
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since sin(x+pi/2) = cos(x) id assume its the taylor of cos(x)
I also need to find the radius of convergence.
the radius is infinity
can you tell me why/how?
first step in constructing a series so to write out the derivative for a while; and solve them for the given a; these become your corrdinants in teh series
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essentially, your constructing a polynomial that moves the same way the function does
when 2 functions bend and move the same (have the same derivatives) they match up along certain conditions
\[f(x)=g(x)\text{ when } f'(x)=g'(x); ...;f^{(n)}{x}=g^{(n)}{x}\]
okay thank you!
can you please help me with another if I post one more?
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i can try
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