Question

Find three consecutive positive integers such that the product of the first and the third is one less than 6 times the second.

Answer 1

You can express these three as
x , x+1 , x+2

The product of the first (x) and the third (x+2) is one (1) less than 6 times the second (6(x+1)

How would you express that equation ?

Answer 2

let numbers be , n, n+1 and n + 2
n(n+ 2) = 6(n + 1) - 1
- solve this for n

Answer 3

thank you so much guys!

Answer 4

yw