Question

the derivative of the function f is given by f'(x)=x^2cos(x^2). How many points of inflection does the graph of f have on the open interval (-2,2)

Answer 1

ummm take the derivative again and equate it to 0

Answer 2

i'm having trouble getting the right derivative :/

Answer 3

you use the product+ chain rule for this
so your derivative would look like this

x^2(derivative of cos (x^2) + (derivative of x^2)(cos(x^2)


To find the derivative of cos(x^2)

(derivative of cos)(x^2)(derivative of x^2)

Answer 4

okay this is the equation i have..

Answer 5

2x(-x^3sin(x^2)+2cos(x^2))=0