Question

Can I use logarithms to solve this? If so, how?
24000 + 3000y = 30000 * 1.04^(y-1)

Answer 1

no, not with the 'y' there on the ground floor

Answer 2

you can certianly cancel a bunch of stuff and get
\[24+3y=30(1.04)^{y-1}\] or maybe even
\[8+y=10(1.04)^{y-1}\] but then you are stuck

Answer 3

okay, then how would i go about solving this word problem:

Answer 4

this girl has two different job offers, job A starting salary is 27000 with an increase of 3000 each year after the first, job B has a starting salary of 30000 with a 4% increase each year after the first year

Answer 5

in how many years will job A's salary be higher than job B's? The answer is obviously two years, but how would you do it mathematically?

Answer 6

when will they be equal?

Answer 7

trial and error

Answer 8

somewhere betwen 2 and 3 years

Answer 9

I made two equations then set them equal to each other, and then whatever answer i got i would round up.
A = 27000 + 3000(y-1)
B = 30000 * 1.04^(y-1)

Answer 10

It's on an open response so i cant just put "guess and check"

Answer 11

A
27,000 30,000 33,000 36,000

B
30,000 31,200 32448, 33745.92

Answer 12

I understand that, but I can't just put a table of the values, I need to show it algebraically. Is there any way to do that?