What value of x will make this an arithmetic series? x, 0.5x + 7, 3x - 1...
HINT: In an arithmetic series, each difference is the same.
For that to be an arithmetic series, x must satisfy the ff: (0.5x+7)-x=(3x-1)-(0.5x+7)
I know that the difference is the same. But I still can't find the value for x.
If the series is S1,S2,S3,S4,... then, S2-S1 = S3-S2 = S4-S3 = Sn - S(n-1)
You that means you can set up that equation that blockolder set up for you. Solve that equation for x.
I still seem to be unable to solve it =S
You sure?
Yes.
x, 0.5x + 7, 3x - 1... Treat it like any normal algebra problem. Simplify. Gather the xs on one side and the constants on the other. (0.5x+7) - x = (3x-1)-(0.5x+7) -0.5x+7 = 2.5x -8 -3x +7 = -8 -3x = - 15 x = (-15/-3) = 5
what if instead of 3x - 1, we had 3x + 1, what would happen then?
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