The highway mileage m in miles per gallon for a compact car is approximated by m(s) = -0.025s^2 + 2.45s - 30, where s is the speed in miles per hour. What is the maximum mileage for this compact car to the nearest tenth of a mile per gallon? __________ mi/gal.
also to the nearest whole number as well. I'm so confused. help!
I this question in your parabola or quadratic equation chapter
yes
both
have you bee using graphing calculators
use you graphing calc and plug in for y= your equation
dont have one.
hmmm...oh, you just need to max value for s, right?
yes
remember, the graph will point downwards since the leading term has a -.....remember that?
so you need the max s value which at the vertex...top of the parabola when sketched out....lkooks like the path when you throw a ball up and it comes back down...got the picture?
so you can find the x value of the vertex by using -a/2b....where a is the coeficient of the leading term and b is the coefficient of the second, or linear, term.
ok make since so far.
so you'll have -(-0.025)/2(2.45)......have a regular calculator?
that's backwards.....-b/2a = -2.45/2(-0.025)= 49 so plug in the 49 for s and evaluate....
are you still there??
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