Question

Find the lowest common denominator that would eliminate the fractions in this equation.

3a/7+2/3=7/9

Answer 1

So the answer is 36

Answer 2

seven times nine is sixty three

try it and see what happens.
\[\frac{3a}{7}+\frac{2}{3}=\frac{7}{9}\]
multiply both sides by sixty three
\[63\times\frac{3a}{7}+63\times\frac{2}{3}=63\times\frac{7}{9}\]
\[9\times 3a+23\times 2=7 \times 7\]
\[27a+46=49\]

Answer 3

\[27a=3\]
\[a=\frac19\]