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Use the given zero to find all the zeros of the function f(x)=x^3+x^2+9x+9 r=3i
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r = 3 is not a 0
its r=3i
ah ok.
if 3i is a root, then so is -3i
so (x-3i) and (x+3i) are factors, so a factor is (x-3i)(x+3i) = x^2 + 9
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We divide by this factor to get x + 1
so the last root is -1
All three roots are : 3i, -3i, and -1
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