Question

5(x+7)=5x+35

Answer 1

If you're asking if that's correct. It is.

Answer 2

5(x+7)=5x+35
5x+35=5x+35

Answer 3

why is it different than this problem 5(x-7)=3(x-2)+2x
5x35=3x-6+2x
5x=5x-6+35
5x-5x=35-6
x cancels out so no solution

Answer 4

You're correct in thinking that no solutions exist.

Answer 5

For the first problem: \[5(x-7)=5x-35\;\; \Longrightarrow \;\;5x-35=5x-35\]So you get \(0=0\). This is always true, so \(x\) has infinite solutions.

In the second problem, you can simplify to get \(0=29\). This is obviously not true. Therefore there are no solutions.

Answer 6

KingGeorege is right. I agree with King

Answer 7

thanks guys