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solve using the quadratic formula
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|dw:1335054291077:dw|
|dw:1335054291077:dw|
Your equation is -2y^2 -3y +3 = 0 Solutions are y = [-b +/- sqrt(b^2 - 4ac) ] /2a where a=-2, b=-3, c=3.
Substitute the values of a, b, and c to solve.
Hint: Your answer will involve the sqrt of 33.
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|dw:1335054510373:dw| i subtract -3y and add 3 rite?
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