5-2=3 (5)
7-4=3(7)
10-8=2
6-3=3
8-5=3
*like a boss*
OpenStudy (lgbasallote):
lol =))))) so that's what ishaan meant
OpenStudy (lgbasallote):
random numbers lol becca
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OpenStudy (anonymous):
It's not...post your original question again..it makes perfect sense
OpenStudy (lgbasallote):
whered you get 5, 2, 7, 4 , etc
OpenStudy (anonymous):
can you just post the orignal...then I shall show you :D
OpenStudy (lgbasallote):
1 + 1 = 3
2 + 2 = 3
3 + 3 = 3
4 + 4 = 2
5 + 5 = ?
OpenStudy (lgbasallote):
show me then
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OpenStudy (lgbasallote):
Hint 2: "simple" arithmetic haha
OpenStudy (anonymous):
okay 3 +2 =5
4+3=7
6+3=9
8+2=10
5+5=3 ( I saw the answer so I kinda cheated)
then go back through the original and
5-2=3
7-4=3
10-8=2
6-3=3
8-5=3
OpenStudy (zepp):
becca, you kinda did the same thing but in the opposite way..?
OpenStudy (lgbasallote):
lol 6-3 and 8-5 =))) that's still not the formula
OpenStudy (anonymous):
darn, oh well hhahaa I have failed you
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OpenStudy (lgbasallote):
should i tell the answer now...
OpenStudy (anonymous):
69 c;
OpenStudy (anonymous):
No.
OpenStudy (lgbasallote):
okay..
OpenStudy (anonymous):
Okay post it now! This better be a very good one :P
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OpenStudy (lgbasallote):
that makes me nervous that it might not be good enough :P but what the heck it's a riddle...
OpenStudy (lgbasallote):
this was a two part riddle..the first is the "simple" arithmetic part...it means to use kindergarten arithmetic...that means 1 + 1 is not 2..but becomes 11
so...
1+1 = 11
2+ 2 = 22
3+3 = 33
4+4 = 44
5+5 = 55
6+6 = 66
7+7 = 77
8+8 = 88
9+9 =99
11 = ElEvEn <- 3 Es
22 = TwenTy Two <- 3 Ts
33 = ThirTy Three <- 3 Ts
44 = Forty Four <- 2 Fs
55 = FiFty Five <- 3 Fs
66 = Sixty Six <- 2 Ts
77 = Seventy Seven <- 2 S
88 = Eighty Eight <- 2 Es
99 = NiNety NiNe <- 4 Ns
good enough @FoolForMath :troll:
OpenStudy (anonymous):
But I wouldn't have guessed it in a million years.
OpenStudy (anonymous):
There is not symmetry on the letters of repetition right?
OpenStudy (anonymous):
Okay got it! Good one :)
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OpenStudy (anonymous):
Thanks for sharing!
OpenStudy (lgbasallote):
i dont know..it's just the number of repetitions of the first letter...asnaseer suggested it while he was solving a harder problem haha