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How do you find the focus of a parabola with the equation x=4(y-2)^2 +3 ??
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it means vertex right?
it means focus
you have to find the vertex yes :) but then measure from it up by "a"
y^2 = 4ax is the general setup for this where a is the distance we seek
(x-3) = 4(y-2)^2 x = 4y^2 1/4 x = y^2 4a = 1/4 ; a = 1/8
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since our vertex is at 3,2 ; and we open up to right; is say the focus is at (3+1/8 , 2)
i think my a is off http://www.wolframalpha.com/input/?i=%28x-3%29+%3D+4%28y-2%29%5E2
a = 1/16 :)
thats better; (3+1/16, 2)
the key tho is to know the geometric eq for the parabola ....
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Thank you! This was really helpful!
yw
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