Question

Solve for x: (x - 9)2 = 1
So far I got
(x-9)2=1
(√x-92)=√1
x-9=1
x=1=9
x=10

was told to...take the square root of both sides. So x - 9 = +-1.
Then what? I'm confused.

Answer 1

Hint: \[(x-9)^2 = 1\]\[x - 9 = \pm \sqrt{1}\]

Answer 2

x=10,8

Answer 3

In general, when

\[a^2 = b\], \[a = \pm \sqrt{b}\]

Answer 4

\[\sqrt{a^2} = \left| a \right|\]

Answer 5

Expand getting: \[x ^{2}-18x + 81 = 1\]\[x ^{2}-18x + 80=0\]

Answer 6

\[(x-8)(x-10)=0\]\[x=10\]\[x=8\]

Answer 7

Thanks.