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OpenStudy (anonymous):
can you tell me where this is concave up and down pls
OpenStudy (anonymous):
do you have the second derivative?
OpenStudy (anonymous):
4/(3 x^(5/3))
OpenStudy (anonymous):
looks good to me. how about the function... is it defined everywhere (continuous)?
OpenStudy (anonymous):
think so
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OpenStudy (anonymous):
ok. so looking at your second derivative, it does not exist at x=0, correct?
OpenStudy (anonymous):
it doesnt
OpenStudy (anonymous):
ok. to check for concavity you'll need to split up your intervals as (-inf, 0) and (0, inf).
pick any x value in each of these intervals and stick it into the second derivative.
for each x you chose, tell me what the sign is (positive or negative)...
OpenStudy (anonymous):
ive got a positive value on (0,inf) and negative on (-inf,0)
OpenStudy (anonymous):
good.
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OpenStudy (anonymous):
what does a negative sign for your second derivative mean? it means the slope of the tangent line is decreasing... so the shape of your graph will look like this:|dw:1335146881709:dw|