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Mathematics 9 Online
OpenStudy (anonymous):

x−6x^(1/3) concavity pls?

OpenStudy (anonymous):

can you tell me where this is concave up and down pls

OpenStudy (anonymous):

do you have the second derivative?

OpenStudy (anonymous):

4/(3 x^(5/3))

OpenStudy (anonymous):

looks good to me. how about the function... is it defined everywhere (continuous)?

OpenStudy (anonymous):

think so

OpenStudy (anonymous):

ok. so looking at your second derivative, it does not exist at x=0, correct?

OpenStudy (anonymous):

it doesnt

OpenStudy (anonymous):

ok. to check for concavity you'll need to split up your intervals as (-inf, 0) and (0, inf). pick any x value in each of these intervals and stick it into the second derivative. for each x you chose, tell me what the sign is (positive or negative)...

OpenStudy (anonymous):

ive got a positive value on (0,inf) and negative on (-inf,0)

OpenStudy (anonymous):

good.

OpenStudy (anonymous):

what does a negative sign for your second derivative mean? it means the slope of the tangent line is decreasing... so the shape of your graph will look like this:|dw:1335146881709:dw|

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