find the area of rhombus with p=100 and a diagonal of 48
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OpenStudy (anonymous):
what is p?
OpenStudy (anonymous):
Area of a rhombus is given by: \(\frac 12 \times\) Product of the diagonals.
OpenStudy (anonymous):
perimeter
OpenStudy (anonymous):
what do i do with the perimeter
OpenStudy (anonymous):
If P is the perimeter then P/4 is the length of the one side right?
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OpenStudy (anonymous):
yeah 25
OpenStudy (anonymous):
i don't understand what to do with that
OpenStudy (anonymous):
Okay, There is a property relating side and the two diagonals of a rhombus:
side\( ^2 \) = ( \(\frac12\times \) one diagonal)\(^2\) + (\(\frac12\times \) other diagonal)\(^2\)
So, you can use this to find the length of the other diagonal and then use it to find the area.
OpenStudy (anonymous):
so one diagonal would equal 96
OpenStudy (anonymous):
One diagonal is 48 which is given and the other should be 14. Area = 336 sq units.
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OpenStudy (anonymous):
Does it help?
OpenStudy (anonymous):
how did you get 14?
OpenStudy (anonymous):
Set x = the other diagonal, now using the formula|dw:1335148488460:dw|