Question

10x^2-3x-1=0

Answer 1

10x^2-3x-1 = 0
We can factor this either as (10x +/- ?)(x +/- ?) or (5x +/- ?)(2x +/- ?)
Since the 'factors' of 1 are... 1, and the value in the middle is 3, I'm going to go with the second set of factors.
This means (5x + 1)(2x - 1) = 0
(we can check this using the FOIL method, which shows 5x*2x + 2x + -5x + -1
= 10x^2 -3x -1)
If you need to find the zeros, we break the factors apart and set each of them equal to 0.
5x + 1 = 0
5x = -1
x = -1/5

2x - 1 = 0
2x = 1
x = 1/2

Answer 2

Thanks

Answer 3

You're very welcome!