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Mathematics 9 Online
OpenStudy (lgbasallote):

could someone teach me the steps of curve tracing? calculus-wise.. Please do not give copy-paste answers. I don't need technical terms to hurt my mind lol. I appreciate own words :DDD Note: This is not a riddle :P

OpenStudy (lgbasallote):

would be appreciated if you state it differential calculus-wise..

OpenStudy (apoorvk):

Okay, give us an example equation @lgbasallote , so that we can explain that to you.

OpenStudy (lgbasallote):

hmmm well im just reviewing so i dont know any spcific questions.... but i guess i can spout some random variables.... \(\mathsf{x^5 + 3x^4 + 5x^3 - 2x^2 - x + 6}\)

OpenStudy (anonymous):

You are to plot this equation?

OpenStudy (anonymous):

What's curve tracing?

OpenStudy (lgbasallote):

hmm curve sketching...

OpenStudy (lgbasallote):

\(\LARGE \mathtt{\text{can you do it ishaan bhaiya??}}\)

OpenStudy (anonymous):

I can plot quadratic, and some defined functions but this, THIS! is beyond me :(

OpenStudy (lgbasallote):

oh...okay...

OpenStudy (lgbasallote):

like i said...i spouted random variables....is it impossible?

OpenStudy (anonymous):

wait... we can differentiate the equation get the inflection points?

OpenStudy (lgbasallote):

i guess just a cubic function like \(\mathtt{ 7x^3 + 3x^2 - 2x + 1}\)

OpenStudy (lgbasallote):

what about in just a cubic function? how to graph it calculus-wise? i think it's more possible

OpenStudy (mimi_x3):

well, for cubic differentiate it then find the stationary points then the point of inflexion..

OpenStudy (mimi_x3):

To determine the nature find the second derivative.

OpenStudy (lgbasallote):

and stationary points are....?

OpenStudy (mimi_x3):

stationary points are the maximum and minimum.

OpenStudy (mimi_x3):

like when the points are constant.

OpenStudy (lgbasallote):

it's taking the first derivative and finding the value of x right?

OpenStudy (lgbasallote):

and inflection point is second derivative?

OpenStudy (mimi_x3):

yeah x and y then to determine the nature you find the second derivative and sub the x and y values in. Then the second derivative is show ifs its a max or min,

OpenStudy (mimi_x3):

i don't think your drawing is write its to the fifth degree..not quartic.

OpenStudy (mimi_x3):

right*

OpenStudy (lgbasallote):

second derivative determines maximum and minimum via max -> negative; minimum -> positive..do i have it right?

OpenStudy (mimi_x3):

yeah i guess so..

OpenStudy (mimi_x3):

wait

OpenStudy (lgbasallote):

yes?

OpenStudy (mimi_x3):

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