Question

how to solve using the quadratic formula?
4x^2+3x-4=0

Answer 1

The quadratic formula is

(-b +or- sqrt(b^2-4*a*c))/2a

Answer 2

the normal equation is put as

a^2*x+b*x+c

here,
a=4
b=3
c=-4

Answer 3

my answer is... x=15+_ squrt of 105/6

Answer 4

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]\[x=\frac{-3 \pm \sqrt{3^2-4(4)(-4)}}{2(4)}\]\[x=\frac{-3 \pm \sqrt{9+64}}{8}\]\[x=\frac{-3 \pm \sqrt{73}}{8}\]

Answer 5

damn... what did i do wrong...... lol

Answer 6

Can you show your workings?

Answer 7

oh .. haha im lookin at another problem ... lololololol im dumb.. i got it correct

Answer 8

Oh... Nice that you got it correct :)

Answer 9

ya.. im havin alot of trouble in this section and i just dont have confidence in my answers..

Answer 10

i only have 2 more 2 ask. then ive got what i need.