how to solve using the quadratic formula?
4x^2+3x-4=0

Question

how to solve using the quadratic formula?
4x^2+3x-4=0

anonymous · Answer

The quadratic formula is

(-b +or- sqrt(b^2-4*a*c))/2a

anonymous · Answer

the normal equation is put as

a^2*x+b*x+c

here, 
a=4
b=3
c=-4

anonymous · Answer

my answer is... x=15+_ squrt of 105/6

callisto · Answer

$$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$$$$x=\frac{-3 \pm \sqrt{3^2-4(4)(-4)}}{2(4)}$$$$x=\frac{-3 \pm \sqrt{9+64}}{8}$$$$x=\frac{-3 \pm \sqrt{73}}{8}$$

anonymous · Answer

damn... what did i do wrong...... lol

callisto · Answer

Can you show your workings?

anonymous · Answer

oh .. haha im lookin at another problem ... lololololol im dumb.. i got it correct

callisto · Answer

Oh... Nice that you got it correct :)

anonymous · Answer

ya.. im havin alot of trouble in this section and i just dont have confidence in my answers..

anonymous · Answer

i only have 2 more 2 ask. then ive got what i need.