solve for x : x-4+ 3/x=0 any ideas? i came to the solutions (1,3).
rewrite the equation x - 4 = -3/x multply each term by x x^2 - 4x = -3 add 3 to both sides x^2 - 4x + 3=0 factorise (x -3)(x+1) x = 3, -1
@campbell_st I think it should be x - 4 = -3/x you missed the sign. So the solution is, x^2 -4x = -3 or, x^2 -4x +3 =0 or, x^2 -3x -x +3 =0 or, x(x-3) -1 (x-3) =0 so, x = 1,3 @brandon871861 you are right.
ummm thats what my solution is... please check
thank you very much yall.. greatly appriciate it!!
the solution isn't (1,3) as this indicates an ordered pair... the solution is x = 1, 3
i dont understand when you say x=1, 3
is it the same things as saying... x=1 and x=3? i dont see how x can be both 1 and 3 if thats the case..
yes when you substitute x = 1 or x = 3 into the equation the solution is 0... the ordered pairs are (1, 0) and (3, 0) your solution (1, 3) is x = 1 and y = 3 the equation you solved can be drawn on the number plane... and the solutions x=1 and x = 3 is where it cuts the x axis
this is a simple graph |dw:1335169762174:dw|
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