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Mathematics 8 Online
OpenStudy (anonymous):

See Attachmentt ... PLeasee Helpp Me !

OpenStudy (chaise):

You look cute. I might see if I can help.

OpenStudy (anonymous):

2. What is the sum ? (1 point) 2b

OpenStudy (chaise):

You have got to cross multiply fractions in order to add them together when the denominator is not the same. I hope that's what you're asking.

OpenStudy (anonymous):

yeaa , thankss :)

Parth (parthkohli):

Did you still get the answers or can I explain it? :)

OpenStudy (anonymous):

suree :) uu can explain it :)

Parth (parthkohli):

Just get the LCM of the denominators. Multiply the numerators by the same number you multiply to the denominator.

OpenStudy (anonymous):

yea thts wat i did lol ..

Parth (parthkohli):

Awright..Can you solve all the answers now?

OpenStudy (anonymous):

yea

Parth (parthkohli):

Kaythen

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

3. What is the sum( the first attachment is the problem !) the othaa are the multiple choice ? (1 point)

OpenStudy (anonymous):

\[\LARGE {1\over g+2}+{3\over g+1}=\] \[\LARGE ={g+1\over (g+2)(g+1)}+{3(g+2)\over (g+1)(g+2)}\] \[\LARGE ={g+1+3g+6\over (g+2)(g+1)}\] can you do it now ? :)

OpenStudy (anonymous):

sorry I forgot to smile :) lol.

OpenStudy (anonymous):

is it 3/G + 3? i suck at math srry lol

OpenStudy (anonymous):

\[ \LARGE ={g+1+3g+6\over (g+2)(g+1)}={4g+7\over(g+2)(g+1) }\] your third option seems to match :)

OpenStudy (anonymous):

oh okay , i see now :) thanks !

OpenStudy (anonymous):

My pleasure xD

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