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. Evaluate: t^-ca^ca, where c = 3, a = 2, and t = -4
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just substitute \[\LARGE t^{-c}\cdot a^c\cdot a\] \[\LARGE (-4)^{-3}\cdot 2^3\cdot 2\] \[\LARGE \left(\frac{1}{-4}\right)^{3}\cdot 16\] Continue... :)
the ^c is suppose to be with the (a) that you multiplied with at the end
well.. I'm confused, O_O you should have used parentheses ... is it \[\Huge t^{-ca^{ca}}\] can you draw it ? :(
|dw:1335207292275:dw|
ok... |dw:1335207492157:dw|
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