Question

Write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and passes through the point (2, 6).

Answer 1

perpendicular of y=2/3x-4 is y=-3/2x, then use the equation for finding intercept, (y-y1)=-3/2(x-x1)+b to solve

Answer 2

?
can you help me like step by step

Answer 3

\[ m2 = -1/m1\]
this is perpendicular slope
replace in the equation.
gives y = -3/2x +b
replace point cooordinates to find b
gives 6 = -3/2 * 2 +b
b =9
y = -3/2x+9

Answer 4

im still confused

Answer 5

is that my answer?

Answer 6

we only know that the slope is prependicular.
it is the opposed of the inverse of another slope , by definition
next, when we have the m2, we replace a known point couple to determine an unknown value b
the following is how to know the slope
2 x -3y =12
-3y = 12 -2x
y = -4+2/3x
the slope is before the x, so it is 2/3
applay formula, you get - 1 / 2/ 3 = -3/2