Find the equation of the tangent line to the gven curve at the given point y=2sinx at (pi/6, 1)
Am i suppose to use unit circle..?
Tangent line at ( pi/6, 1) is: y - 1 = m (x - pi/6 ) m = f'( pi /6) Can you do it?
do i u use the unit circle for pi/6? i tried it without using unit circle, and get some really weird answer
f`(number) = 0 ?
f' for this equation would be, if I'm not mistaken 2cos(x)
yea i think f' is 2cos (x) too
as for your question if you use the unit circle. yea; I do believe you use the value of cos at pi/6
then i will get critical numbers using unit circle what do i do with it?
f' (x) = 2 cosx -> f' ( pi/6 ) = .....
Chlorophyll is right, use the equation he gave above and plug in what you know already. That should give you the answer. y-1=m(x-pi/6) where m=2cos(x)
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