The area of a square is (4x^2-12x+9) sq.cm.The width of a rectangle is five cm greater than a side of the square while the length of the rectangle is twice the side of the square.What is the area, in sq.cm. of the rectangle? please show me the steps.
A.16x^2-12x-14
B.8x^2+10x-12
C.4x^2-8x-16
D.4x^2+2x-2
E.None of these

Question

The area of a square is (4x^2-12x+9) sq.cm.The width of a rectangle is five cm greater than a side of the square while the length of the rectangle is twice the side of the square.What is the area, in sq.cm. of the rectangle? please show me the steps.
 A.16x^2-12x-14 
B.8x^2+10x-12 
C.4x^2-8x-16 
D.4x^2+2x-2 
E.None of these

blockcolder · Answer

One side of the square is given by sqrt(4x^2-12x+9)=2x-3 cm.
If L and W are the length and width of the rectangle, then L=2x+2 cm. and W=4x-6 cm.
Now what is the area of the rectangle?

anonymous · Answer

@blockcolder  @sammy12  block is correct!! but block u can make it more easier!

blockcolder · Answer

@Rohangrr You mean like this:
LW=(2x+2)(4x-6)=4(x+1)(2x-3)
??

anonymous · Answer

Is it 8x^2-4x-12
The answer is E .Is it Right!

blockcolder · Answer

Yes. Yes it is. :D

anonymous · Answer

Thank you so much

blockcolder · Answer

No problem. :D