Question

If the average of x numbers is y, find the least integer?

Answer 1

Some concept is needed as well :S

Answer 2

x - y is the least integer

Answer 3

How do you work that out?

Answer 4

for example 3 is the greatest integer and 1 is the least integer. 3 would be x and 2 would be y. x - y is the least integer. It is the only solution i could think of.

Answer 5

1)Figure out the largest number.
2) Find the difference between mean and largest number.
3) If the mean is x and the difference is y, then subtract y from x.

Answer 6

Mean(1,2,3,4,5) => Mean = 3, Largest = 5, Difference is 2 so 3 - 2 = 1

Answer 7

@ParthKohli Let me do that, give me tw o mins, I'll get back.

Answer 8

"1)Figure out the largest number."

Is that easier than figuring out the smallest?

Answer 9

@estudier I answered that to Zeerak. His last question was about finding the largest number.

Answer 10

@estudier Double the mean and subtract 1.

Answer 11

3,5,8,39,100 Average 31

Answer 12

Ifthe average of 7 consecutive odd numbers is 23, what is the average of the greatest integer in this series?

Your provided formula 2y-1 fails for me in this. 23*2 =46
46-1 = 45 which is incorrect.

Answer 13

Hence I cnt figure out the largest number in this series!

Answer 14

"7 consecutive odd numbers" Ah! More information...

Answer 15

Oops. CAUGHT

Answer 16

The 4th odd number would be the mean.

Answer 17

My formula works only when the series starts from 1... hmmm

Answer 18

You could set up an equation then.

Answer 19

You can't find the least integer without more info..

Answer 20

[(x-6) + (x - 4) + (x - 2) + x + ...... (x + 6)] / 7

Answer 21

This is a way to do it.

Answer 22

Hmm, let me post another question.