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How do i factor x^2+4x-12?
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Note: -6 * 2 = -12. Try using that to solve.
That didn't help at all
well i would start with finding the factors of 12
would it be (4x-6)(4x+2)?
Do the 4's cancel out?
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The form that you are looking for is: (x + a) ( x - b) Where a * b = -12 and a + 6 = +4 So, (x + 6) (x - 2) = x^2 + 4x - 12
after looking at the factors 1,12 2,6 3,4 find which one subtracted from the other equals the middle term 4
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