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Mathematics 19 Online
OpenStudy (anonymous):

Factor the polynomial 4x eponent2 -4

OpenStudy (kropot72):

This is the difference of two squares. Therefore the factorisation is: \[4x ^{2}-4=4((x+1)(x-1))\]

OpenStudy (anonymous):

Yup..So the factor of \[4x ^{2}- 4\] is (x+1) (x-1)

OpenStudy (kropot72):

NO. The required factors are as follows: \[4x ^{2}-4=4\times (x+1)(x-1)\] 4 is one of the faactors

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