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Mathematics 17 Online
OpenStudy (anonymous):

multiply & simplify : x^2-4/x^2-1*x+1/x+2

OpenStudy (kropot72):

Both the numerator and denominator of the first term are the difference of two squares and can be factorised:\[((x+2)(x-2)(x+1))\div((x+1)(x-1)(x+2))\] This reduces to :\[((x+2)(x-2))\div((x-1)(x+2)\]

OpenStudy (kropot72):

Sorry, forgot to add a closing bracket.

OpenStudy (anonymous):

|dw:1335325303972:dw| I am right?

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