Question

√9x-8=√10

Answer 1

is the x under the square root ?

Answer 2

yes

Answer 3

do you have to find x?

Answer 4

Solve

Answer 5

Square root of 9x-8 equals squrae root of 10

Answer 6

Multiple choice
a.) x=1
b.) x=2
c.) x=12
d.) none of the above

Answer 7

I got
9x-8 = 10
9x = 10 + 8
9x = 18
x = 18 / 9
x = 2

Answer 8

Is this correct?

Answer 9

\[\sqrt{9x}\] = 8 + \[\sqrt{10}\]
square both sides
9x = 64+ 10 + \[16\sqrt{10}\]
so now we add integers at the left side and divide by 9
x = 74/9 + 16/9 \[\sqrt{10}\]

Answer 10

or
Square root of (9x) - 8= square root of (10)
9x (-8)^2 = 10
9x + 64 = 10
9x = 10 -64
9x = -54
x = -54/9 = -6

Answer 11

No, remember that
(a+b)^2 = a^2 + 2ab + b^2
(a-b)^2 = a^2 - 2ab + b^2
proof is
(a+b)*(a+b)= a*a + a*b + b*a + b*b = a^2 + a*b + a*b + b^2 = a^2 + 2ab + b^2
and for second one
(a-b)*(a-b)= a*a + a*(-b) + (-b)*a + (-b)*(-b) = a^2 - a*b - a*b + b^2 = a^2 - 2ab + b^2

Answer 12

got it

Answer 13

Thank you