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NEED SERIOUS HELP PLEASE .!!!! Input the equation of the given line in standard form. The line including (3, 1) and (-2, 3)
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eqn of a line passing thru (x1,y1) and (x2,y2) is given by y-y1=((y2-y1)/(x2-x1))*(x-x1)
that didnt help me any
take (3,1) as (x1,y1) and (-2,3) as (x2,y2) now plug in the values in the formula i mentioned above
that formula is confusing me .. I completely suck at math .
carefully look at the parenthesis ur answer shud b y=(-2/5)x+11/5
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y=mx+c is the standard form of a line m=slope of the line c= y intercpt cut by the line
i thought the formula was y=mx+b ?
m=(y2-y1)/(x2-x1) u can take it b,c,d or whatever u like since its a constant
do u get it now?
yeah
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y=-(2/5)x+11/5
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