Question

NEED SERIOUS HELP PLEASE .!!!!
Input the equation of the given line in standard form.

The line including (3, 1) and (-2, 3)

Answer 1

eqn of a line passing thru (x1,y1) and (x2,y2) is given by
y-y1=((y2-y1)/(x2-x1))*(x-x1)

Answer 2

that didnt help me any

Answer 3

take (3,1) as (x1,y1) and (-2,3) as (x2,y2)
now plug in the values in the formula i mentioned above

Answer 4

that formula is confusing me .. I completely suck at math .

Answer 5

carefully look at the parenthesis ur answer shud b y=(-2/5)x+11/5

Answer 6

y=mx+c is the standard form of a line
m=slope of the line
c= y intercpt cut by the line

Answer 7

i thought the formula was y=mx+b ?

Answer 8

m=(y2-y1)/(x2-x1)
u can take it b,c,d or whatever u like since its a constant

Answer 9

do u get it now?

Answer 10

yeah

Answer 11

y=-(2/5)x+11/5