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Solve using the quadratic formula. Then use a calculator to approximate, to three decimal places, the solutions as rational numbers x^2 + 6x+ 4= 0
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The quadratic formula states that the solutions to a quadratic equation is\[x=(-b \pm \sqrt{b^2-4ac})/2a\]You get a,b, and c from the equation. a=1, b=6, and c=4. Now you can substitute these values into the formula.\[x=(-6 \pm \sqrt{6^2-4(1)(4)})/2(1)\]\[x=(-6 \pm \sqrt{36-16})/2\]\[x=(-6 \pm \sqrt{20})/2\]\[x=(-6 \pm 2\sqrt{5})/2\]\[x=-3 \pm \sqrt{5}\]
thank you tons! that was tripping me up bad!
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