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Mathematics 18 Online
OpenStudy (anonymous):

Verify the trigonometric identity: tan(x)+cot(x)=sec(x)csc(x)

OpenStudy (anonymous):

okai work on L.S= Sinx+cos2x/sinxcosx

OpenStudy (kropot72):

tan(x) + cot(x) = (sin(x)/cos(x)) +(cos(x)/sin(x)) = (sin^2(x) + cos^2(x))/(cos(x) * sin(x) =1/cos(x)*sin(x) = sec(x)csc(x)

OpenStudy (anonymous):

how do you know which side to work on ?

OpenStudy (anonymous):

always work on the complicated side

OpenStudy (anonymous):

okay, i'll try and let you know how it goes >.<

OpenStudy (anonymous):

if you get stuck tell me, that one is complicated XD

OpenStudy (anonymous):

hows it going so far? Did you figure out whats next?

OpenStudy (anonymous):

I went with LHS= sinx/cosx +cosx/sinx =(sin^2x+cos^2x)/sinxcosx and now im stuck again >.< I feel im going in circles lol

OpenStudy (anonymous):

AWESOME, you got it okai, now that will equal 1/sinxcosx

OpenStudy (anonymous):

okay then what ? o.O

OpenStudy (anonymous):

LOL Okai if you remeber what does 1/sinx? and what is 1/cosx?

OpenStudy (anonymous):

equal..sorry XD

OpenStudy (anonymous):

cosx and sec x ! YOU ARE AMAZING. shpanks

OpenStudy (anonymous):

lol nah im stuck in a trig identity question too :')

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