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OpenStudy (anonymous):
Verify the trigonometric identity: tan(x)+cot(x)=sec(x)csc(x)
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OpenStudy (anonymous):
okai work on L.S= Sinx+cos2x/sinxcosx
OpenStudy (kropot72):
tan(x) + cot(x) = (sin(x)/cos(x)) +(cos(x)/sin(x)) = (sin^2(x) + cos^2(x))/(cos(x) * sin(x)
=1/cos(x)*sin(x) = sec(x)csc(x)
OpenStudy (anonymous):
how do you know which side to work on ?
OpenStudy (anonymous):
always work on the complicated side
OpenStudy (anonymous):
okay, i'll try and let you know how it goes >.<
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OpenStudy (anonymous):
if you get stuck tell me, that one is complicated XD
OpenStudy (anonymous):
hows it going so far? Did you figure out whats next?
OpenStudy (anonymous):
I went with
LHS= sinx/cosx +cosx/sinx
=(sin^2x+cos^2x)/sinxcosx
and now im stuck again >.<
I feel im going in circles lol
OpenStudy (anonymous):
AWESOME, you got it okai, now that will equal 1/sinxcosx
OpenStudy (anonymous):
okay then what ? o.O
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OpenStudy (anonymous):
LOL Okai if you remeber what does 1/sinx? and what is 1/cosx?
OpenStudy (anonymous):
equal..sorry XD
OpenStudy (anonymous):
cosx and sec x ! YOU ARE AMAZING. shpanks
OpenStudy (anonymous):
lol nah im stuck in a trig identity question too :')
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