Question

Find the equation for a line that passes through the point (8,6) and is perpendicular to v = -9i +5j

Answer 1

its been a while since i've done this, so forgive me if i et this wrong lol

Answer 2

oh my bad, I thought that this was in 3D. this is pretty simple then

Answer 3

Yeah I tried using point slope: y-y1 = m(x -x1)

Answer 4

what did you use as your slope?

Answer 5

With a perp. slope of 1/9

Answer 6

the slope of the vector is -5/9

Answer 7

so to be perpendicular to that, the slope of your new line needs to be 9/5

Answer 8

AHHH!!

Answer 9

9/5x - 72/5 +6

Answer 10

Got it right.. sweet. Thanks guys. So i/j is the slope on these vectors? What if there was to be a k?